(x^2-5x+2)+(x^2+4x+5)-(x^2-6x-42=)

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Solution for (x^2-5x+2)+(x^2+4x+5)-(x^2-6x-42=) equation: 



(x^2-5x+2)+(x^2+4x+5)-(x^2-6x-42=)

We move all terms to the left:

(x^2-5x+2)+(x^2+4x+5)-(x^2-6x-42-())=0

We get rid of parentheses

x^2+x^2-5x+4x-(x^2-6x-42-())+2+5=0



We calculate terms in parentheses: -(x^2-6x-42-()), so:

x^2-6x-42-()

We add all the numbers together, and all the variables

x^2-6x

Back to the equation:

-(x^2-6x)



We add all the numbers together, and all the variables

2x^2-1x-(x^2-6x)+7=0

We get rid of parentheses

2x^2-x^2-1x+6x+7=0

We add all the numbers together, and all the variables

x^2+5x+7=0

a = 1; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·1·7
Δ = -3
Delta is less than zero, so there is no solution for the equation

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